Question

the sum of a no. and its square root is 132 then find the no.​

Answer 1

Answer:

now solve the equation you will get the answer

Answer 2

Answer:

11

Step-by-step explanation:

$let \: be \: assume \: number \: = x \\ then \\ x + {x}^{2} = 132 \\ {x}^{2} + x - 132 = 0 \\ {x }^{2} + 12x - 11x - 132 = 0 \\ x(x + 12) - 11(x + 12) = 0 \\ (x + 12)(x - 11) = 0 \\ x = 11$