the sum of a non-zero number and its reciprocal is 41/20 find the number
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Answer:
x = 5/4 or 4/5
Step-by-step explanation:
let the number be x
⇒x + 1/x = 41/20
⇒20(x² + 1) = 41x
⇒20x² + 20 - 41x = 0
⇒20x² - 41x + 20 = 0
⇒20x² - 16x - 25x + 20 = 0
⇒4x(5x - 4) - 5(5x - 4) = 0
⇒(4x - 5)(5x - 4) = 0
⇒x = 5/4 or 4/5
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