The sum of a number and it's reciprocal is 10/3.find the number.
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let x be the number..
x+1/x=10/3
(x^2+1)3=10x
3x^2-10x+3=0
3x^2-9x-x+3=0
3x(x-3)-1(x-3)=0
3x-1=0. or x-3 =0
x=1/3 or x=3....
hope it helps....!!!
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