Question

The sum of a number and its inverse is -4. The sum of their cubes is?

Answer 1

Step-by-step explanation:

Let the number be x

x+1/x=-4

(x+1/x)cube=(-4)cube

(x)^3+(1/x)^3+3(x)(1/x)(x+1/x)=-64

x^3+1/x^3+3(x+1/x)=-64

x^3+1/x^3+3(-4)=-64

x^3+1/x^3-12=-64

THEREFORE, x^3+1/x^3=-64+12

x^3+1/x^3=-52

Answer is - 52

Pls mark it as BRAINLIST

Answer 2

Answer:

The sum of a number and it's reciprocal is - 4.

Then let us take as this

X+1/x=-4

X^2 +4x+1=0

X(x+4)+1=0

(x+4)(x+1)=0

So x=-4/-1

Then x^3+1/x3=

-64+1/-64=4097/64=-64.01

Hope it helps to you...