Question

the sum of a number and its one third is 60. Find the number

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

45

Step-by-step explanation:

As per the provided information in the given question, we have :

• The sum of a number and its one third is 60.

We are asked to calculate,

• The number.

Let us assume the number as x. According to the question,

$\longmapsto \rm { Number = x}$

$\longmapsto \rm { Number_{(One \; third)}= \dfrac{1}{3}x}$

~The sum of a number and its one third is 60.

$\longmapsto \rm { x+ \dfrac{1}{3}x = 60}$

Step 1 : Taking L.C.M in the R.H.S to make the denominator same and performing addition.

$\longmapsto \rm { \dfrac{3x + x}{3} = 60}$

Step 2 : Performing addition in the numerator.

$\longmapsto \rm { \dfrac{4 x}{3} = 60}$

Step 3 : Transposing 3 from L.H.S to R.H.S. Since, it is in the form of division in L.H.S. It'll become in the form of multiplication in R.H.S.

$\longmapsto \rm { 4x = 60\times 3}$

Step 4 : Performing multiplication in R.H.S.

$\longmapsto \rm { 4x =180}$

Step 5 : Transposing 4 from L.H.S to R.H.S. Since, it is in the form of multiplication in L.H.S. It'll become in the form of division in R.H.S.

$\longmapsto \rm { x =\cancel{\dfrac{180}{4}}}$

Step 6 : Dividing 180 by 4.

$\longmapsto \bf { x =45}$

∴ The number is 45.