Question

the sum of a number and its positive square root is 6/25 find the number

Answer 1

HEY BUDDY YOUR ANSWER IS GIVEN BY UDIT

let the number be x

then GIVEN

x+x^2=6/25

25x^2+25x=6

$d = \sqrt{25 {}^{2} -4 \times 25 \times ( - 6) }$

d=35

x=(-25+35)/50 or x=(-25+-35)/50

x=1/5 or x= 6/5

thanks

Answer 2

Let x be the number,

Therefore positive square root = √x

Sum of number and its positive square root = $\frac{6}{25}$

Therefore x+√x=$\frac{6}{25}$

Let x = y²

(y)²+(√y)²=$\frac{6}{25}$

y²+y=$\frac{6}{25}$

25y²+25y-6=0

Therefore solving the equation we get,

y=$\frac{1}{5} or\frac{-6}{5}$

But x = y²

x=$(\frac{1}{5})^2$or$(\frac{-6}{5})^2$

x=$\frac{1}{5}$or$(\frac{-6}{5})^2$

x= 1/25 or x=36/25