the sum of a number and its reciprocal is 21/30. find the number. explain with steps plsss
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Let the number be x.
Reciprocal of the number= 1/x
ATQ,
x + 1/x = 21/30
= 30( x2 + 1) = 21x
= 30x2 + 30 - 21x =0
= 30x2 -21x + 30 =0
x= -b+ under root b2 - 4ac / 2a
= -(-21) + under root (-21)2 -4*30*30 / 2* 30
= 21 + under root 441 - 3600 / 60
= 21 + under root -3159 /60
Root in negative is not possible. Thus there exists no solution.
Hope this helps.................Happy to help!!!
Let the number be x.
Reciprocal of the number= 1/x
ATQ,
x + 1/x = 21/30
= 30( x2 + 1) = 21x
= 30x2 + 30 - 21x =0
= 30x2 -21x + 30 =0
x= -b+ under root b2 - 4ac / 2a
= -(-21) + under root (-21)2 -4*30*30 / 2* 30
= 21 + under root 441 - 3600 / 60
= 21 + under root -3159 /60
Root in negative is not possible. Thus there exists no solution.
Hope this helps.................Happy to help!!!
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Answered by
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hope it be helpful
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