the sum of a number and its reciprocal is 65/28 find the number
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Let the number be x,
then according to the question ;
x+(1/x) = 65/28
x^2 + 1 = 65x/28
x^2 -(65/28)x +1 = 0
(x)^2-(2ĂxĂ65/56)+ (65/56)^2-(65/56)^2+1=0
(x+65/56)^2 = 4225/3136 -1
x + 65/56 = â 1089/3136
x = 33/56 +- 65/56
x = 98/56 or x= -32/56
x = 49/28 or -16/28
x= 7/4 or -4/7
hope this helped you,
plzzz mark as brainliest .......... !
then according to the question ;
x+(1/x) = 65/28
x^2 + 1 = 65x/28
x^2 -(65/28)x +1 = 0
(x)^2-(2ĂxĂ65/56)+ (65/56)^2-(65/56)^2+1=0
(x+65/56)^2 = 4225/3136 -1
x + 65/56 = â 1089/3136
x = 33/56 +- 65/56
x = 98/56 or x= -32/56
x = 49/28 or -16/28
x= 7/4 or -4/7
hope this helped you,
plzzz mark as brainliest .......... !
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3
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