Question

The sum of a number and its reciprocal is 8/3. represent this situation in the form of quadratic equation.
1) 3x²-8x+3=0
2) x²-3x+1=0
3) 8x²-3x+1=0
4) 3x²-3x+8=0

explain??✔✔
better answer✌ i will mark brainliest✌​

Answer 1

Let the number be x

$x + \frac{1}{x} = \frac{8}{3}$

$\frac{ {x}^{2} + 1 }{x} = \frac{8}{3}$

$3( {x}^{2} + 1) = 8x$

$3 {x}^{2} + 3 = 8x$

$3 {x}^{2} + 3 - 8x = 0$

$3 {x}^{2} - 8x + 3 = 0$

Option a is correct

Answer 2

Step-by-step explanation:

option 1)

3×^2-8x+3=0