Question

the sum of a number and its reproicel is 10/3. find 5je number

Answer 1

A+1/A=10/3,

(A²+1)/A=10/3,

3A²+3=10A,

3A²-10A+3=0,

3A²-(9+1)A+3,

3A²-9A-A+3=0,

3A(A-3)-1(A-3)=0,

(A-3)(3A-1)=0,

then
A=3

Answer 2

Hey

Here is your answer,

Let the unknown number be x and it's reciprocal be 1/x.

X + 1/x = 10/3
X^2 + 1 = 10x/3
3x^2 - 10x + 3 = 0
3x^2 - 9x - x + 3 = 0
3x ( x-3 ) - 1 ( x-3 ) = 0
( 3x-1 ) ( x-3 ) = 0
3x-1 = 0
X = 1/3
X-3 = 0
X = 3

Therefore, the unknown number is 3.

Hope it helps you!