Question

the sum of a number and its square is nine times the highest number. find it
Step by step plz explanation.. ​

Answer 1

the number is = 9 or -1

Step-by-step explanation:

Let the number = x

its square =x²

the highest number = (x+1)

now acc.to question

x+x² = 9(x+1)

x+x² = 9x+9

x²-8x-9 = 0

(x-9)(x+1) = 0

x = 9 or x = -1

Check:

9+81 = 9×10 True

-1+(-1)² = 9×0 True

Hope this will help you :)

Answer 2

Answer:

Let the number = x

its square =x²

the highest number = (x+1)

now acc.to question

x+x² = 9(x+1)

x+x² = 9x+9

x²-8x-9 = 0

(x-9)(x+1) = 0

x = 9 or x = -1

Check:

9+81 = 9×10 True

-1+(-1)² = 9×0 True

Step-by-step explanation:

Mark me as Brainliest