Question

.The sum of a number and square of the number gives 42. Find the number​

Answer 1

Answer: hope it helps

Step-by-step explanation:

x+x2=42 x2+x-42=0 (x-7)(x+6)=0 x=7 or -6

Answer 2

Answer:

6

Step-by-step explanation:

As per the question,

we get, x + x² = 42

x² + x - 42 = 0

Solve this equation

$\frac{-b\frac{+}{-}\sqrt{b^{2}-4ac } }{2a}$

a = 1

b = 1

c = -42

$\frac{-1\frac{+}{-}\sqrt{1^{2}-(4*1*-42) } }{2*1}$

$\frac{-1\frac{+}{-} \sqrt{1 + 168} }{2}$

$\frac{-1\frac{+}{-}\sqrt{169} }{2}$

$\frac{-1\frac{+}{-}13 }{2}$

$\frac{-1-13}{2}$     &      $\frac{-1+13}{2}$

$\frac{-14}{2}$       &         $\frac{12}{2}$

x = -7  and 6

Avoid '-'ve values

So ,x = 6

6 + 36 = 42