Question

The sum of a number of 2 digit and the number formed by reversing the digit is 110 and the difference of digit is 6 .find the number

Answer 1

Let once place digit=a tens=b
hence, no.=10b+a
reverse of no.=10a+b
diff of digits=a-b=6. or a=6+b
A.T.Q
10b+a+10a+b=110
11(a+b)=110
a+b=10
6+b+b=10
2b=4
b=2
a=6+2=8

hence no. is 28

and if b=6+1
no.=82

Ans.=82,28

Answer 2

Answer:

Let the no. be 10x+y

10x+y+10y+x = 110

11x+11y =110

11(x+y) = 110

x+y = 10

x-y = 6

Add both the equations

2x = 16

x = 8

y=2

Hence, the number is 82 or 28