the sum of a number of 2 digits and of the number formed by reversing the digits is 110, and the difference of the digits is 6 . Find the number.
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let the number be x and y
x-y= 6 ....i
2 digit number 10x+y
on reserving 10y+x
10x+y+10y+x=110
11x+11 y =110
11 (x+y)=110
x+y= 10 ......ii
on additional i and it
x-y =6
×+y=10
-----------
2x= 16
×= 8
then putting the value of y from equation i
x-y =6
8-y =6
y=6+8
=14
hence the number is 10x+y
10×8+14
80+14
94
I don't know it is right ya wrong
x-y= 6 ....i
2 digit number 10x+y
on reserving 10y+x
10x+y+10y+x=110
11x+11 y =110
11 (x+y)=110
x+y= 10 ......ii
on additional i and it
x-y =6
×+y=10
-----------
2x= 16
×= 8
then putting the value of y from equation i
x-y =6
8-y =6
y=6+8
=14
hence the number is 10x+y
10×8+14
80+14
94
I don't know it is right ya wrong
saniakouser:
sorry it is wrong
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