Question

The sum of a number of two digit and of the number formed by reversing the digits is 110 , and the difference of the digits of the digit is 6 . find the number unit digit is greater than the ten 's place.​

Answer 1

Answer:

tens digit is -3

unit digit +9

Step-by-step explanation:

tens + unit digit=  10(-3) + 1(+9)    -------- ORIGINAL NO.

on reversing the digits

tens + unit digit= 10(+9) + 1(-3)    ----------new no.

now add them

-30+ 9     +      90-3    =   66