The sum of a number of two digits and of the no. Formed by reversing the digit is 110
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Let the no. be 10(x+y)
reversed digit =10(y+x)
sum=10(x+y)+(10y+x)=110
You can solve it then .
reversed digit =10(y+x)
sum=10(x+y)+(10y+x)=110
You can solve it then .
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