Question

The sum of a number of two digits and of the number formed by everting two digits is 110 and the
difference of the digits is 6. Find the number.
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Answer 1

Answer:let once place digit-a tens-b

hence, no.=10b+a

reverse of no.=10a+b

diff of digits-a-b-6. or a=6+b

A.T.Q

10b+a+10a+b=110

11(a+b)=110

a+b=10

6+b+b=10

2b=4

b=2

a=6+2=8

hence no. is 28.

and if b=6+1

no.=82

Ans.-82,28

Explanation:

Answer 2

Answer:

Explanation:

10a+b

10b+a

(10a+b)+(10b+a)=110

b=a+6

(10a+(a+6))+(10(a+6)+a)=110

11a+11a+66=110

22a=44

a=2

b=a+6=2+6=8

the original number = 82

reversed number = 28