The sum of a number of two digits and of the number formed by reversing the digits is 110,and the differnece of the digits is 6. Find the number.
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1st digit = x
2nd digit = x -6
(10x +(x -6)) + (10(x -6) +x) = 110
10x +x -6 +10x -60 +x = 110
22x = 110 +6 +60
22x = 176
x = 176/22
x = 8
1st digit = x = 8
2nd digit = x -6 = 8 -6 = 2
Your number: 82
Check: 82 + 28 = 110, 8 -2 = 6
2nd digit = x -6
(10x +(x -6)) + (10(x -6) +x) = 110
10x +x -6 +10x -60 +x = 110
22x = 110 +6 +60
22x = 176
x = 176/22
x = 8
1st digit = x = 8
2nd digit = x -6 = 8 -6 = 2
Your number: 82
Check: 82 + 28 = 110, 8 -2 = 6
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