The sum of a number, two-thirds of itself, one half of
itself and one-seventh of itself is equal to 97. Find the
number.
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Let the no. be x
2/3x+1/2x+1/7x=97
32+21+6/42=49/42
7/6
# the answer is 7/6
2/3x+1/2x+1/7x=97
32+21+6/42=49/42
7/6
# the answer is 7/6
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