The sum of a numerator and denominator of a fraction is 18. If the denominator is increased by 2, the fraction reduces to 1/3. Find the fraction.
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Let the numer be x & denom be y..
- x+y= 18.............(1)
- x/y+2 =1/3
- 3x=y+2
- x=(y+2)/3
- put this value in eq 1
- x+y=18
- (y+2)/3+y=18
- (y+2+3y= 18×3
- 4y+2 =54
- 4y=54-2
- 4y= 52
- y= 52/4
- y= 13
- put the value of y in eq 1
- x+y=13
- x+ 13=18
- x= 18- 13
- x= 5
Hence req. fraction = x/ y = 5/13 .
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