Question

the sum of a positive number and its square is 38 find the number​

Answer 1

Answer:

IS ANSWER

Step-by-step explanation:

Answer 2

Answer:

let, the number be $x$

square of $x = x {}^{2}$

now,

$x + x {}^{2} = 380$

$x + x {}^{2} - 380 = 0$

$x {}^{2} + x - 380 = 0$

$x {}^{2} + 20x - 19x - 380 = 0$

$(x {}^{2} + 20) + ( - 19x - 380) = 0$

$x(x + 20) - 19(x + 20) = 0$

$(x + 20)(x - 19) = 0$

$x + 20 = 0 \\ x = - 20$

$x - 19 = 0 \\ x = 19$

So, the value of $x$ can be $19 \: or \: - 20$

but,

in question it is given a positive number

So, the value of $x = 19$

hope it helps u

:)