the sum of a series of 5 consecutive odd numbers is 195 the second largest number of the series is 5 less than
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CONSIDER AN AP
FIRST TERM OF AP = A
SECOND TERM OF AP = A + 2
THIRD TERM OF AP = A + 4
AND SO ON...
COMMON DIFFERENCE = 2
S = N/2(2A+(N-1)D)
S = 5/2(2A+8)
195 = (10A+40)/2
390 = 10A+40
10A = 350
A = 35
1ST CONSECUTIVE ODD NUMBER = 35
2ND CONSECUTIVE ODD NUMBER = 37
3RD CONSECUTIVE ODD NUMBER = 39
4TH CONSECUTIVE ODD NUMBER = 41
5TH CONSECUTIVE ODD NUMBER = 43
PLZ MARK IT AS BRAINLIEST ANSWER AND DROP A ♥
FIRST TERM OF AP = A
SECOND TERM OF AP = A + 2
THIRD TERM OF AP = A + 4
AND SO ON...
COMMON DIFFERENCE = 2
S = N/2(2A+(N-1)D)
S = 5/2(2A+8)
195 = (10A+40)/2
390 = 10A+40
10A = 350
A = 35
1ST CONSECUTIVE ODD NUMBER = 35
2ND CONSECUTIVE ODD NUMBER = 37
3RD CONSECUTIVE ODD NUMBER = 39
4TH CONSECUTIVE ODD NUMBER = 41
5TH CONSECUTIVE ODD NUMBER = 43
PLZ MARK IT AS BRAINLIEST ANSWER AND DROP A ♥
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