Question

The sum of a series of 5 consecutive odd numbers is 195 the second largest number of the series is 5 less than the second higjest number if even series.if the 40% of the second lowest number of even series

Answer 1

Answer:

          "  The numbers are 29 , 34 , 39 , 44 , 49 "

Step-by-step explanation:

Given that the numbers are Odd numbers.

Let the numbers are

          a - 2 d , a - d , a , a + d , a + 2 d  .......(i)

Then according to the given condition

⇒    a - 2 d + a - d + a + a + d + a + 2 d = 195

⇒    a + a + a + a + a = 195

⇒   5 a = 195

⇒       a = 39

Also given that The difference = d = 5

Putting values in (i), we get

⇒  a - 2 d , a - d , a , a + d , a + 2 d

⇒ 39 - 2(5) , 39 - 5 , 39 , 39 + 5 , 39 +2(5)

⇒ 29 , 34 , 39 , 44 , 49

   "  The numbers are 29 , 34 , 39 , 44 , 49 "

Verification:-

29 + 34 + 39 + 44 + 49 = 195

I hope it will help you.