Question

The sum of a two digit no. and the no.formed by interchanging the digits is 132

Answer 1

let the digits be a and b,where b is the unit number and a is the tenth place number..

so according to the given condition

(10a+b)+(10b+a) = 132

(11a+11b) = 132

a + b = 12....(1)

so better find combinations of a and b such that their digit sum is 12.. as shown in eq (1)

while we add the original two digit obtained number with the reversed number..the sum should b 132 ( given in the question)

so the two digit number will be either 75 or 57