The sum of a two digit no. and the no. formed by reversing the order of digits is 66.If the two digits differ by 2,find the no.. How many such numbers are there.
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The number is 24. when reversing the digits we get 42. and 24+42=66. The other number which satisfies this equation is 42.
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There Are Such 2 Numbers. They Are 42 & 24.
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