The sum of a two digit no and the no obtained by interchanging its digits is 99. Find the no
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Let the no in
one's digit be =x
ten's digit be =10(x)
=10x
On interchanging
Let the no in
ten's digit be 10x
one's digit be x
Adding them
x+10x+10x+x=99
22x=99
x=99/22
=4.5×10
45
Thus the nos are 45 and 54.
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