the sum of a two digit no. and the no. obtained by interchanging its digits ,is always a multiple of ...........
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The answer is 11.
Proof : Let the one place digit of a number is y and that of ten is x.
So, number = 10x + y.
When it will be reversed then new number = 10y + x.
Now,
Sum of these numbers
= 10x + y + 10y + x
= 11x + 11y
= 11 ( x + y ).
Therefore the answer is 11.
Proof : Let the one place digit of a number is y and that of ten is x.
So, number = 10x + y.
When it will be reversed then new number = 10y + x.
Now,
Sum of these numbers
= 10x + y + 10y + x
= 11x + 11y
= 11 ( x + y ).
Therefore the answer is 11.
Anonymous:
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