Question

The sum of a two digit no. and the no. obtained by reversing the digit is66 if the digit of no. differ by2, find the number

Answer 1

here is your solution

Answer 2

Answer:

Given

Two digit number

10 X + y

As given case 1 be

10x+y+10y+x=66

11x+11y=66

11(x+y)=66

x+y=6. -@1

As per case 2

x-y=2. -@2

On adding and subtracting both the equations we get

x+y=6. x+y=6

+X-y=+2. -x+y=-2

2x=8 2y = 4

X=4 Y=2

Hence the two digit numbers are 24 &42.

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