the sum of a two digit no and the no obtained when reversing the digit is 99. if the digits differ by 3, find the no.
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Answered by
11
IN short, we can find the answer in the following way :
Answer is 63.
99 = 81 + 18 ( 8 - 1 = 7, so it's not the required answer)
99 = 72 + 27 ( 7 - 2 = 5, so it's not a required answer)
99 = 63 + 36 ( 6 - 3 = 3, this is the required answer as according to the question, the difference between the digits is 3)
So, the required answer will be 63.
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Answer is 63.
99 = 81 + 18 ( 8 - 1 = 7, so it's not the required answer)
99 = 72 + 27 ( 7 - 2 = 5, so it's not a required answer)
99 = 63 + 36 ( 6 - 3 = 3, this is the required answer as according to the question, the difference between the digits is 3)
So, the required answer will be 63.
HOPE THIS HELPS YOU DEAR...
PLZ MARK MY ANSWER BRAINLIEST IF YOU FIND IT USEFUL...
whytho:
this wasn't useful to me. I need an answer with variables and all
let the no. be 10x + y,ATQ use eqs 11x + 11y = 99 and |x-y| = 3
u read in
this also correct
Answered by
25
Thanks for asking question
Hay dear according to the question your answer is
99 = 63 +36 (6-3= 3) here the difference between three digit is 3
so,
the required answer is 63
I hope it's help you
Hay dear according to the question your answer is
99 = 63 +36 (6-3= 3) here the difference between three digit is 3
so,
the required answer is 63
I hope it's help you
why it can't be 36
66+33=99(6-3=3) the answer is 3 then the reversing to digits by same number
11x+11y=99 =11(x+y)=99 x+y=9 ,x+y=±3,3+y=9=)y=9-3=6. x=3 y=6
thats what i am saying ans van be both 36,63
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