Question

The sum of a two digit no is 13. If the no. Is subtracted from the one obtained by interchanging the didgits the result is 45. What is the no.

Answer 1

Let the ten's place digit be x and one's place digit be y.

therefore, ATQ, x+y=13.

Original no.= 10x+y.

Reversed no.= 10y+x

ATQ,

10y+x-(10x+y)=45

10y+x-10x-y=45

-9x+9y=45

Now,

(x+y=13)*9

=9x+9y=117

(-9x+9y=45)+(9x+9y=117)

=18y=162

y=162/18

hence, y=9.

x+y=13

x+9=13

x=13-9

hence x=4

Original no.= 10x+y

10*4+9=40+9

=49....answer.


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Answer 2

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