the sum of a two digit no. is 9 . the no. obtained by interchanging the digit exceed the orignal no. by 45 . find the no.
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The answer is 54.........
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if two digit number let X+Y=9
two digit number soo 10(X)+Y
here interchange the number exceeds 45..soo
(10x+(9-x))-(10(9-x)+x=45
answer 72
two digit number soo 10(X)+Y
here interchange the number exceeds 45..soo
(10x+(9-x))-(10(9-x)+x=45
answer 72
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