the sum of a two digit number and reserve two digit number is a multiple of
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Let the 2 -digit number be 10x + y
Reverses d=2 - digit number = 10y + x
Sum of this 2 number = 10x + y + 10y + x
= 11(x+y)
The sum of a two digit number and reserve two digit number is a multiple of 11.
Hope this helps you.
Answered by
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Answer:
In this case, the relevant number property to remember is that the sum of two two-digit numbers whose units and tens digits have been reversed is always a multiple of 11, and the difference of such numbers is always a multiple of 9.
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