the sum of a two digit number and the number formed by reversing the digits is always divisible by
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Answer: Answer is 11
Step-by-step explanation:
let the original number be 10x + y
then the number obtained by reversing the digit will be
10y + x
now applying the condition ;
sum of the two number = (10x + y ) + (10y + x)
= 11x + 11y
= 11(x + y)
which is always divisible by 11
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