Question

the sum of a two digit number and the number formed by interchanging it's digits is 88. If the sum of the sum and difference of the digits of the number is 8, what is the number?​

Answer 1

Answer: 44

Step-by-step explanation:

Let the number be of form 10x+y

where x = digit at tens place, y = digit at ones place.

According to Question

(10x+y) + (10y+x) = 88 - Equation 1

(x+y) + (x-y) = 8 -Equation 2

on solving Equation 1,we get

11x+11y= 88

dividing both sides by 11,

x+y = 8 - EQUATION 3

on solving Equation 2,we get

2x= 8

x = 4

On putting value of x in EQUATION 3,

y= 4

Number = 10x+y = 40+4 = 44.

Hope it helps..

Answer 2

Answer:44 i guessed it

Because

4+4=8also4-4=0and8+0=8

So i thought this is the answer

Tell th correct answer if this is wrong pleaseee