the sum of a two digit number and the number formed by interchanging its digits is 88. if the sum of the sum and difference of the diigits of the number is8, what is the number?
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Answer:
Answer: 44
Step-by-step explanation:
Let the number be of form 10x+y
where x = digit at tens place, y = digit at ones place.
According to Question
(10x+y) + (10y+x) = 88 - Equation 1
(x+y) + (x-y) = 8 -Equation 2
on solving Equation 1,we get
11x+11y= 88
dividing both sides by 11,
x+y = 8 - EQUATION 3
on solving Equation 2,we get
2x= 8
x = 4
On putting value of x in EQUATION 3,
y= 4
Number = 10x+y = 40+4 = 44.
Hope it helps..
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