The sum of a two digit number and the number formed by interchanging the digits is 132. If 12 is added to the number, the new number becomes 5 times the sum of the digits. Find the number.
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Answered by
9
- Sum of 2 digit no. and the no. formed by interchanging the digits is 132
- If 12 is added to no. the new no. becomes 2 the sum of digits
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- Find the original number
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- Let the original no. be 10x + y
- No. formed by interchanging the digits = 10y + x
ATQ
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ATQ to 2nd statement :-
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- Multiply eq ( i ) by 5
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- Add eq ( ii ) and ( iii )
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- Putting value of y in eq ( i )
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- Finding the digit
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- Required number = 48
Answered by
4
Answer:
48
Step by Step explanation:
Let the number be xy
Then the number is 10x+y
Interchanging the digits, we get yx
That is 10y+x
10x + y + 10y + x = 132
11x+11y = 132
11(X+y) = 132
x + y = 132/11
X + y = 12 (equation 1)
It is given that
10x+y+12 = 5(X+y)
10x+y+12 = 5x + 5y
5x-4y= -12 (equation 2)
(equation 1) is multiplied by 5
Then 5x+5y = 60
5x-4y = -12
Subtract equation 2 from equation 1
we get
9y=72
y = 8
X+y = 12
X+ 8 = 12
X = 12-8
X = 4
the number is 48
and the interchanged number is 84
so 48+84= 132...
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