Question

the sum of a two digit number and the number obtain by reversing the digits is 66. if the digits of a number differ by 2 find the number.how many such numbers are there?​

Answer 1

Answer:

42

Step-by-step explanation:

let the original number be 10x + y

then other number obtained by reversing the digit is 10y + x

applying condition;

10x + y + 10y + x = 11 x + 11 y = 66

=> x + y = 6 .....................eqn (1)

also the numbers differ by 2 so that we can write this as

x - y = 2 ..........................eqn (2)

solving equations 1 and 2 gives

x = 4 and y = 2

Hence the original number is 42

Answer 2

Answer:

I hope it is helpful.....................

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