Question

The sum of a two digit number and the number obtain by reversing the order if its digits is 121 and the two digits differ by 3 find the number

Answer 1

Answer:

74  & 47

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Step-by-step explanation:

Let say number = 10x + y

Reversed number = 10y + x

sum = 11x + 11y = 121

x + y = 11     - Eq A

either x - y =3     Eq B

or

y-x = 3           Eq C

2x = 14 so x = 7 & y = 4   Adding Eq A + Eq B

2y = 14 so y = 7 & x = 4   Adding Eq A + Eq C

so numbers are

74  & 47