Question

the sum of a two digit number and the number obtained reversing the digit is 66. if the digit of the number differ by 2 find the number

Answer 1

let original no. = 10x + y, reversed no. = 10y + x.
now,
10x + y + 10y + x = 66
11x +11y = 66
x + y = 6
given is x - y = 2 
add both equations
we get, 2x = 8
x = 4 and then y = 2
so, the original number is 42. ANSWER.
thanks...

Answer 2

The right answer is 24 or 42.