The sum of a two digit number and the number obtained be x and y, reversing the digit is 66. If the digit of the number differ by 2, find the number.
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Let us assume x and y are the two digits of a number.
Therefore, The two digit number = 10x + y and the reverse number is 10y + x
Given:
10x + y + 10y + x = 66
11x + 11y = 66
x + y = 6 -------------1
y = 6 - x
Also given:
x - y = 2 ---------------2
By adding equation 1 and equation 2
2x = 8
x = 4
Therefore, y = 6 - x = 6 - 4 = 2
The two digit number = 10x + y = (10 * 4) + 2 = 42
Therefore, The two digit number = 10x + y and the reverse number is 10y + x
Given:
10x + y + 10y + x = 66
11x + 11y = 66
x + y = 6 -------------1
y = 6 - x
Also given:
x - y = 2 ---------------2
By adding equation 1 and equation 2
2x = 8
x = 4
Therefore, y = 6 - x = 6 - 4 = 2
The two digit number = 10x + y = (10 * 4) + 2 = 42
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5
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