Math, asked by ramanpatil194, 1 year ago

the sum of a two digit number and the number obtained by reversing the digit is 55. if the digit of a number differ by 1 find the number

Answers

Answered by yudha16
0

this is the answer hope it helps

Attachments:
Answered by ramanujan515
2

Step-by-step explanation:

let the two digit no. be 10x+y.

where x is 10's digit. y is ones place.

reversing. the digits.

10y +x is the new number.

A.T.Q.

=> 10x+y+10y+x =55

11x+11y=55

11{x+y}=11{5}

x+y = 5.{eq.1}

=> x-y =1{eq.2}

solving 1 and 2.

2x=6

x=3. substitute in {eq.1}

3+y=5

y=2.

Required number.

10x+y = 10(3)+2

=32.

by Mathematics secretary.EGAMS.,CDM.

Mark as brainliest please.

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