the sum of a two digit number and the number obtained by reversing the digit is 55. if the digit of a number differ by 1 find the number
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Step-by-step explanation:
let the two digit no. be 10x+y.
where x is 10's digit. y is ones place.
reversing. the digits.
10y +x is the new number.
A.T.Q.
=> 10x+y+10y+x =55
11x+11y=55
11{x+y}=11{5}
x+y = 5.{eq.1}
=> x-y =1{eq.2}
solving 1 and 2.
2x=6
x=3. substitute in {eq.1}
3+y=5
y=2.
Required number.
10x+y = 10(3)+2
=32.
by Mathematics secretary.EGAMS.,CDM.
Mark as brainliest please.
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