Question

The sum of a two digit number and the number obtained by reversing its digits
is 121. Find the number if its units place digit is greater than the tens place digit
by 7.
​

Answer 1

Answer:

29

Step-by-step explanation:

10x +y +20y + x=121

11x+11y=121

x+y=11(divide 11 on both the sides)

x+x+7=11

2x=4

x=2

therefore 11-2 = 9

do the no. is 29

Answer 2

10x +y +20y + x=121

11x+11y=121

x+y=11(divide 11 on both the sides)

x+x+7=11

2x=4

x=2

therefore 11-2 = 9

do the no. is 29