Question

The sum of a two-digit number and the number obtained by interchanging the digits is 143. If the digit at unit place is 3 more than the digit at the tens place,find the original number​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let the digits at tens and unit place be X. and Y. respectively.

Now,A.TQ.

(10X+Y) + (10Y+X)=. 143

11X +11Y=. 143

11(X+Y)=143

X+Y=13. >(eq1)

Also,

Y=X+3. >eq2

substituting the value of Y from eq 2 to eq1

X+X+3=13

2X=10

X=5

Y=8

The number is 58

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