Question

The sum of a two digit number and the number obtained by reversing the order of its digits is 121 . If the digits in unit's and ten's place are 'x' and 'y' respectively .​

Answer 1

Answer:

x+y = 11

Step-by-step explanation:

If the digits in unit's and ten's place are 'x' and 'y' respectively, then

initial number = 10y + x

reversed number = 10x + y

According to Question

Initial Number + reversed number = 121

10y + x + 10x + y = 121

11 (x+y) = 121

x+y = 11

Hence the required linear equation representing the statement is x+y = 11.

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Answer 2

Step-by-step explanation:

$\huge\bold\red{let}$

unit's place digit = x

ten's place digit = y

The original two digit number

→ ( 10 × y) +( 1 × x )

$\huge\boxed{\fcolorbox{cyan}{green}{10y~+~x}}$

The reversed two digit number

→ ( 10 × x ) + ( 1 × y )

$\huge\boxed{\fcolorbox{cyan}{pink}{10x~+~y}}$

The sum of original and reversed number is 121

→ ( 10y + x ) + ( 10x + y ) = 121

→ 11x + 11y = 121

→ 11 ( x + y ) = 121

→ ( x + y ) = 121 / 11

→ x + y = 11

$\huge\boxed{\fcolorbox{cyan}{yellow}{x~+~y~-~11~=~0}}$