The sum of a two digit number and the number obtained by reversing the Order of the digits is 165.if the digits differ by 3 find the number , tens digit is bigger than the units digit
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Given:
Sum of two digit number and the number obtained by reversing the digits=165.
Difference between the two digits=3.
To Find:
The required number.
Solution:
Let, 10x+y be the two-digit number.
Then, the numbers obtained by reversing the two-digit number=10y+x.
According to question,
10x+y+10y+x=165
=11x+11y=165
=11(x+y)=165
=x+y=15.......equation(1)
Also, x-y=3...........equation(2)
On adding equation (1) and (2)
we get, x+y+x-y=15+3
2x=18
x=9.
Now, x-y=3
9-y=3
so,y=6
Therefore the required number is 96.
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