Question

The sum of a two digit number and the number obtained by reversing the digit is 110. The difference between the digits is 4. Find the number

Answer 1

let the two digit no. be 10x+y
Reverse of this will be 10y+x
given sum of both is equal to 110
i.e 10x+y10y+x= 110
11x + 11y = 110
11(x+y) = 110
x+y= 10. (1)....
given difference is 4
x-y =4 (2)....
Eliminating (1).. and (2)....
x+y = 10
x-y = 4
this gives that
x= 7 and y = 3
therefore the no. is 73

Hope this helps u...
Cheers...

Answer 2

HI !

Let the original no: be 10x + y and the reversed no: be 10y+x

a.t.q.,

10x + y + 10y + x = 110

11x + 11y = 110

x + y = 10             ----> (1)

also,

x - y = 4           ----> (2)

Adding equations 1 and 2.

2x = 14

x = 7

x - y = 4

y = 3

The no: is ->

10x + y = 10*7 + 3 = 73

The no: is 73