Question

The sum of a two digit number and the number obtained by interchanging the digits is 99.if the digit is tens place exceed digit at unit place by 3 find the number

Answer 1

Step-by-step explanation:

Suppose that digit in the unit's place be x and the digit in the ten's place be y . Then,

Number=10y+x

The number obtained by interchanging the digits is 10x+y

According to the given conditions,

(10y+x)+(10x+y)=99

=11x+11y=99

=11(x+y)=99

=x+y=99/11

=x+y=9 ......1

And,x−y=±3 ......2 (given)

On solving equation 1 and 2 ,we get

x=6,y=3 or x=3,y=6

Hence the required number is either63 or 36

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