Question

The sum of a two-digit number and the number obtained by reversing the digits is 110. If the difference of the digits of the number is 4, find the number. How many such numbers are there​

Answer 1

Step-by-step explanation:

HII THERE.

Let the two digit no. be 10x+y

Let the two digit no. be 10x+yReverse of this will be 10y+x

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 110

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 110

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110x+y= 10. (1)....

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110x+y= 10. (1)....given difference is 4

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110x+y= 10. (1)....given difference is 4x-y =4 (2)....

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110x+y= 10. (1)....given difference is 4x-y =4 (2)....Eliminating (1).. and (2)....

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110x+y= 10. (1)....given difference is 4x-y =4 (2)....Eliminating (1).. and (2)....x+y = 10

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110x+y= 10. (1)....given difference is 4x-y =4 (2)....Eliminating (1).. and (2)....x+y = 10x-y = 4

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110x+y= 10. (1)....given difference is 4x-y =4 (2)....Eliminating (1).. and (2)....x+y = 10x-y = 4this gives that

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110x+y= 10. (1)....given difference is 4x-y =4 (2)....Eliminating (1).. and (2)....x+y = 10x-y = 4this gives thatx= 7 and y = 3

Let the two digit no. be 10x+yReverse of this will be 10y+xgiven sum of both is equal to 110i.e 10x+y10y+x= 11011x + 11y = 11011(x+y) = 110x+y= 10. (1)....given difference is 4x-y =4 (2)....Eliminating (1).. and (2)....x+y = 10x-y = 4this gives thatx= 7 and y = 3therefore the no. is 74

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