The sum of a two digit number and the number obtained by reversing the order of its digits is
121 and the two digits difer by 3. Find the number.
Answers
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Step-by-step explanation:
Let the units digit be y
let the tens digit be x
number = 10x + y
On reversing the digits , the no.becomes 10y + x
10x + y + 10y + x = 121
11x + 11y = 121
11(x+y) = 121
x + y = 121/11
x + y = 11 -----------(1)
Given,difference of digits = 3
x - y = 3 ------------(2)
Adding both equations,(elimination method)
x + y = 11
x - y = 3
---------------
2x = 14
x = 14/2
x = 7
put x = 7 in equation (1)
7 + y = 11
y = 11-7
y = 4
Number = 10x + y
Number = 10(7)+4
Number = 70 + 4
Number = 74
HOPE IT HELPS...
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