Question

The sum of a two digit number and the number obtained by reversing the order of its digits is

121 and the two digits difer by 3. Find the number. ​

Answer 1

Step-by-step explanation:

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Let the units digit be y

let the tens digit be x

number = 10x + y

On reversing the digits , the no.becomes 10y + x

10x + y + 10y + x = 121

11x + 11y = 121

11(x+y) = 121

x + y = 121/11

x + y = 11 -----------(1)

Given,difference of digits = 3

x - y = 3 ------------(2)

Adding both equations,(elimination method)

x + y = 11

x - y = 3

---------------

2x = 14

x = 14/2

x = 7

put x = 7 in equation (1)

7 + y = 11

y = 11-7

y = 4

Number = 10x + y

Number = 10(7)+4

Number = 70 + 4

Number = 74

HOPE IT HELPS...