The sum of a two-digit number and the number obtained by reversing its digits is 121. Find the number if it’s unit place digit is 5. EXPLAIN
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Answer:
65
Step-by-step explanation:
Let the no. be 10x + y, where x and y are tens and units digit respectively.
Given y=5
Therefore, number = 10x+5
After reversing the digits, the tens digit = y = 5, and ones digit = x.
So, new no. = 10(5) + x = 50 + x.
Given, (10x+5) + (50+x) = 121
11x+ 55 = 121
x + 5 = 11
x = 6.
Therefore, number = 10x + y = 10(6) + 5= 60 + 5 = 65
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